Java 8 Programs
Java 8 Real Time Interview Coding Questions and Answers
We use Stream.concat() to combine two lists and apply:
✔ distinct() to remove duplicates
✔ sorted() with Comparator.reverseOrder()
✔ collect(Collectors.toList()) to store results
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import java.util.Arrays; import java.util.Comparator; import java.util.List; import java.util.stream.Collectors; import java.util.stream.Stream; public class ConcatenateListDemo { public static void main(String[] args) { List<String> strList1 = Arrays.asList("Java", "Nodejs", "C"); List<String> strList2 = Arrays.asList("JavaScript", "Angular", "Java", "C"); List<String> combinedList;
Stream.concat(strList1.stream(), strList2.stream()) .distinct() .sorted(Comparator.reverseOrder()) .forEach(System.out::println);
System.out.println("--------------------------------------");
combinedList = Stream.concat(strList1.stream(), strList2.stream()) .distinct() .sorted(Comparator.reverseOrder()) .collect(Collectors.toList());
System.out.println("Combined Sorted List : "+ combinedList);
/* List<Integer> list1 = Arrays.asList(10,40,20,30,50); List<Integer> list2 = Arrays.asList(40,70,60); List<Integer> mergedList;
Stream.concat(list1.stream(), list2.stream()) .distinct() .sorted(Comparator.reverseOrder()) .forEach(System.out::println); System.out.println("-----------------------------");
mergedList = Stream.concat(list1.stream(), list2.stream()) .distinct() .sorted(Comparator.reverseOrder()) .collect(Collectors.toList());
System.out.println("Merged Elements : "+ mergedList); */
} } |
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